Which is the balanced chemical equation showing hydrogen peroxide (H2O2) decomposing into hydrogen (H2) and oxygen (O2)? Multipl
1 answer:
Answer:
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation for showing hydrogen peroxide decomposing into hydrogen and oxygen is:
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Answer:
The weight percent of potassium carbonate is 50,8 wt% and of potassium bicarbonate 49,2 wt%
Explanation:
The reactions of potassium carbonate (K₂CO₃) and potassium bicarbonate (KHCO₃) with HCl produce:
K₂CO₃ + 2HCl → 2KCl + CO₂ + H₂O
KHCO₃ + HCl → KCl + CO₂ + H₂O
That means that you need 2 moles of HCl to titrate potassium carbonate and 1 mol to titrate potassium bicarbonate.
The moles of HCl to titrate the mixture are:
0,03416L× = <em>0,02603 mol of HCl</em>
If X is mass of K₂CO₃ and Y is mass of KHCO₃ in the mixture, the moles of HCl to titrate the mixture are equals to:
0,02603 mol = 2X× + Y×
<em>(1)</em>
As the mass of the mixture is 2,122g:
2,122g = X + Y <em>(2)</em>
Replacing (2) in (1):
0,02603 mol = 0,01447 (2,122-Y) + 9,988x10⁻³Y
0,02603 mol = 0,0307 - 0,01447Y + 9,988x10⁻³Y
-4,6778x10⁻³ = -4,4827x10⁻³Y
1,044g = Y <em>-mass of potassium bicarbonate-</em>
Thus:
X = 1,078g <em>-mass of potassium carbonate-</em>
The weight percent of potassium carbonate is:
×100 =<em> 50,8 wt%</em>
The weight percent of potassium bicarbonate is:
×100 = <em>49,2 wt%</em>
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I hope it helps!
Answer : The question is incomplete, the complete question is attached in answer
To calculate the displacement by Ann's driving from north of her house to south;
we have the data as
In north - 10 km
in south - 5 km
total - 15 km
So we can calculate the displacement, which will be,
10 - 5 = 5 km.
Hence, the displacement will be 5 km
To calculate the displacement by Ann's driving from north of her house to south;
we have the data as
In north - 10 km
in south - 5 km
total - 15 km
So we can calculate the displacement, which will be,
10 - 5 = 5 km.
Hence, the displacement will be 5 km