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Mariana [72]
3 years ago
13

E ) The distribution coefficient , Ko ( Cether / C water ) , for an organic substance X at room temperature is 13. What relative

volume of ether to water should be used for the extraction of 94 percent of X from a water solution in single extraction ?
Chemistry
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

Relative volume of ether to water that should be used for the extraction = 1.205

Explanation:

The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).

K = (C₁/C₂)

Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).

If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.

Let the volume of ether required be x mL.

Let the volume of water required be y mL.

Relative volume of ether to water that should be used for the extraction = (x/y)

Mass concentration of the organic substance X in ether = (0.94/x)

Mass concentration of organic substance X in water = (0.06/y)

The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.

13 = (0.94/x) ÷ (0.06/y)

13 = (0.94/x) × (y/0.06)

13 = (15.667y/x)

(x/y) = (15.667/13) = 1.205

Hope this Helps!!!

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If NO₂ molecule written is for Nitrogen dioxide, then, four of the five molecules presented above have no dipole moment and only one of the five molecules, Ozone (0₃), has a dipole moment.

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3) Sulfur hexafluoride, SF₆ - no dipole moment.

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4) Ozone, O₃ - has a dipole moment.

O₃ is polar because there are 18 valence electrons, so the lewis structure would position the central O connected to one single bond and one double bond to connect the other O's. The lone pair on the central O would also mean the molecule was bent, thus making it polar. Therefore, Ozone is a polar molecule with a dipole moment of 0.53 D. The molecule can be represented as a resonance hybrid with two contributing structures, each with a single bond on one side and double bond on the other.

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PCl₅ has a symmetrical geometry, the vector sum of the dipole moments of the different P-Cl bonds cancel each other. Therefore, the overall dipole moment of PCl₅ becomes 0.

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