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Ierofanga [76]
4 years ago
15

What is the density of a rectangle solid with dimensions

Chemistry
1 answer:
Hunter-Best [27]4 years ago
8 0

Answer:

5625000gm/cm^3

Explanation:

volume=w*h*l=25*15*5=1875cm^3

density=mass*volume

=1875*3000

=5625000gm/cm^3

You might be interested in
How many moles are in 4.67 x 10^26 atoms of Iron?
TiliK225 [7]

Answer:

<h2>775.75 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4.67 \times  {10}^{26} }{6.02 \times  {10}^{23} }   \\  = 775.747508...

We have the final answer as

<h3>775.75 moles</h3>

Hope this helps you

4 0
3 years ago
Identical objects are placed in Beaker A and Beaker B. The objects float as shown in the diagram. What can you conclude about th
vodka [1.7K]
<span>I think it is a but dont take me for it. I searched it and thats what I found since liquid in beaker B is more dense then realtivley speaking the object is less dense compared other liquid and floats at a higher level.</span>
3 0
3 years ago
Read 2 more answers
What is the wavelength (in nm) of light with a frequency of- ^^ see picture
Dafna1 [17]

Frequency =6.75×10^14s^{-1}

\\ \sf\longmapsto \lambda=\dfrac{c}{v}

\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8m/s}{6.75\times 10^{14}s^{-1}}

\\ \sf\longmapsto \lambda=0.444\times 10^{-6}m

\\ \sf\longmapsto \lambda=0.4\mu m

7 0
3 years ago
Read 2 more answers
A gas cylinder under constant pressure, such as one with a moveable piston, initially contains 0.25 moles of neon in 5.0 L. If 0
Mandarinka [93]

Answer:

15L will be the final volume

STEPS:

.50 + .25 = .75

.25/5 ÷ .75/x

(.75*5=3.25)

.25x = 3.25

x=15

quizlet

4 0
3 years ago
5. A gas occupies 2000. Lat 100.0 K and exerts a pressure of 100.0 kPa. What volume will
Anna [14]

Answer:

4000 L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 2000 L.

Initial temperature (T1) = 100 K.

Initial pressure (P1) = 100 kPa.

Final temperature (T2) = 400 K.

Final pressure (P2) = 200 kPa.

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using the general gas equation as follow:

P1V1/T1 = P2V2/T2

100 x 2000/100 = 200 x V2/400

Cross multiply to express in linear form.

100 x 200 x V2 = 100 x 2000 x 400

Divide both side by 100 x 200

V2 = (100 x 2000 x 400)/(100 x 200)

V2 = 4000 L

Therefore, the new volume of the gas is 4000 L

5 0
3 years ago
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