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asambeis [7]
2 years ago
9

In AIJK, i = 270 cm, j = 170 cm and _K=122°. Find the area of AIJK, to the

Mathematics
1 answer:
Softa [21]2 years ago
7 0

9514 1404 393

Answer:

  19,463 cm²

Step-by-step explanation:

The area is given by the formula ...

  A = (1/2)ij·sin(K)

Filling in the values, we find the area to be ...

  A = (1/2)(270 cm)(170 cm)·sin(122°) ≈ 19,463 cm²

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53​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the
faltersainse [42]

Answer:

a

   P(X = 5) = 0.2423

b

    P( X \ge  6 )=  0.4516

c

   P( X <  4 )=  0.12694

Step-by-step explanation:

From the question we are told that

   The population proportion is   p = 0.53

    The sample size is  n = 10

Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators        

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly​ five is mathematically represented as

     P(X = 5) =  ^{10}C_5 *  0.53^5 *  (1- 0.53)^{10-5}

=>  P(X = 5) =  252 * 0.04182 *  0.023

=>  P(X = 5) = 0.2423

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is  at least​ six is mathematically represented as

  P( X \ge  6 )=  P( X  = 6) +  P( X  = 7) +  P( X  = 8) +  P( X  = 9) +  P( X  = 10)

=> P( X \ge  6 )=  [^{10}C_6 *  [0.53]^6 *  (1- 0.53)^{10-6}] +  [^{10}C_7 *  [0.53]^7 *  (1- 0.53)^{10-7}] +  [^{10}C_8 *  [0.53]^8 *  (1- 0.53)^{10-8}] +  [^{10}C_9 *  [0.53]^9 *  (1- 0.53)^{10-9}] + [^{10}C_{10} *  [0.53]^{10} *  (1- 0.53)^{10-10}]

=> P( X \ge  6 )=  [0.227] +  [0.1464] +  [0.0619] +  [0.0155] + [0.00082]

=> P( X \ge  6 )=  0.4516

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is  less than four is mathematically represented as

    P( X <  4 )=  P( X  = 3) +  P( X  = 2) +  P( X  = 1) +  P( X  = 0)

=>  P( X <  4 )=  [^{10}C_3 *  0.53^3 *  (1- 0.53)^{10-3}] +  [^{10}C_2 *  0.53^2 *  (1- 0.53)^{10-2}] +  [^{10}C_1 *  0.53^1 *  (1- 0.53)^{10-1}] +  [^{10}C_0 *  0.53^0 *  (1- 0.53)^{10-0}]

=>  P( X <  4 )=  0.09051  +  0.03 +  0.0059 +  0.000526

=>  P( X <  4 )=  0.12694

5 0
2 years ago
Multiple choice plz plz help! Thanks:)
Minchanka [31]
A- Since the radius is 22, the area is 1520.53, or, 1520.5 simplified.
3 0
3 years ago
Micheal wants to buy 12 pens but he is short of $8.40. If he buys 9 pens, he will have $29.40 left. How much money does he have?
trapecia [35]
All you have to do is subtract the biggest numbers i the problems.
6 0
2 years ago
Need help asap will give brainly, please
Setler [38]

Answer:

g

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I’ll give you brainliest for the first person with an answer
raketka [301]

Answer:

1296mm^2

Step-by-step explanation:

Surface Area of the Rectangular Prism to the left on top of the box:

Area of square = lw, 9mm * 9mm = 81mm, then multiply by 2 because 2 of the squares are a part of the surface, giving <u>162mm^2</u>

Area of a rectangle =lw, 9mm * 9mm = 81mm, then multiply by 2 again, because 2 rectangles are a part of the surface, giving <u>162mm^2</u>

So, the total surface area of the rectangular prism to the left on top, is 324mm^2

Surface Area of the Triangular Prism:

Area of a triangle: 1/2bh, and our base length would be 12, because we have to subtract 9 from 21 since the base length of the triangle isn't stated. Anyways, A = 1/2bh, so A = 1/2(12)(9) = 54mm^2, but multiply by two, so we get <u>108mm^2</u>.

Area of the rectangle: lw, so 15mm * 9mm = <u>135mm^2</u>

So, the total surface area of the triangular prism is 243mm^2

Surface Area of the Rectangular Prism at the bottom:

Area of the long rectangles in front = lw, 21mm * 9mm = 189mm^2, multiply by 2, <u>378mm^2</u>

Area of the rectangles to the side = lw, 9mm * 9mm = 81mm^2, multiply by 2, <u>162mm^2 </u>

Area of the rectangle at the very bottom = lw, 21mm * 9mm = <u>189mm^2</u>

So, the total surface area of the rectangular prism at the bottom is 729mm^2

Add all the total surface areas of each shape to get the total surface area of the figure:

324mm^2 + 243mm^2 + 729mm^2 = 1296mm^2

The surface area of the figure above is 1296mm^2

<u />

4 0
2 years ago
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