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asambeis [7]
3 years ago
9

In AIJK, i = 270 cm, j = 170 cm and _K=122°. Find the area of AIJK, to the

Mathematics
1 answer:
Softa [21]3 years ago
7 0

9514 1404 393

Answer:

  19,463 cm²

Step-by-step explanation:

The area is given by the formula ...

  A = (1/2)ij·sin(K)

Filling in the values, we find the area to be ...

  A = (1/2)(270 cm)(170 cm)·sin(122°) ≈ 19,463 cm²

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8 0
3 years ago
Select the quadrant in which the terminal side of the angle falls.
Sedbober [7]

Answer:

The answer is below

Step-by-step explanation:

Select the quadrant in which the terminal side of the angle falls.

210° terminates in quadrant

-150° terminates in quadrant

390° terminates in quadrant

Solution:

The x and y axis divides the cartesian plane into four equal parts known as the four quadrants.

Angles between 0° and 90° are in the first quadrant, angles between 90° and 180° are in the second quadrant, angles between 180° and 270° are in the third quadrant while angles between 270° and 360° are in the fourth quadrant.

a) Since 210 degrees is between 180° and 270°, hence it terminates in the third quadrant.

b) -150° = 360 - 150 = 210°. Since 210 degrees is between 180° and 270°, hence it terminates in the third quadrant.

c) 390° = 390° - 360° = 30°.

Since 30 degrees is between 0° and 90°, hence it terminates in the first quadrant.

 

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3 years ago
This one-dimensional figure goes on forever in two directions.
Vikki [24]
It’s line always goes in both directions
7 0
2 years ago
9x+16<br> 3<br> &lt;7<br> solve each inequality
Crazy boy [7]

Step-by-step explanation:

9+16×+3

28×<7

35x it's answer can I help

8 0
3 years ago
Thanks for the help!
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Hope you could understand.

If you have any query, feel free to ask.

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