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3 years ago

In AIJK, i = 270 cm, j = 170 cm and _K=122°. Find the area of AIJK, to the

Mathematics

1 answer:

Softa [21]3 years ago

7 0

9514 1404 393

Answer:

19,463 cm²

Step-by-step explanation:

The area is given by the formula ...

A = (1/2)ij·sin(K)

Filling in the values, we find the area to be ...

A = (1/2)(270 cm)(170 cm)·sin(122°) ≈ 19,463 cm²

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Please help

Harman [31]

Answer:

we get $\mathbf{gf(2)=-\frac{1}{3}}$

Step-by-step explanation:

We are given:

$f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1$

We need to find value of $gf(2)$

$gf(2)=g(f(2))$

First putting f(x) inside of g(x) and then putting x=2

$gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}$

Now putting x=2 to find $gf(2)$

$gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}$

So, we get $\mathbf{gf(2)=-\frac{1}{3}}$

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2 years ago

The width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the

Vladimir79 [104]

The answer will be 35ft2

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3 years ago

If the diameter of a circle is 12.6 what is the circumference

serg [7]

The answer is C≈39.58

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Read 2 more answers

Study the statements carefully.

Elan Coil [88]

Answer

x = unidentified

Explanation

If 12÷3=4 and 12 = 4×3, that means 6÷0=x and x×0=6.

This isn't possible because any number divided by 0 is unidentified.

7 0

2 years ago