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jok3333 [9.3K]
3 years ago
11

(If I think it’s right I’ll make you brainless answer) Mark is building a scale model of his car as shown in the diagram. The ac

tual car has a height of 10 feet and the model has a height of 1 foot at the same place.
A. What is the actual length of the car? Show your work.
B. Mark has model wheels with a diameter of 6 inches. If the actual wheel radius is 2.25 feet, will they be in proportion with his model? Justify your answer.

Type your answer below:
Mathematics
1 answer:
sasho [114]3 years ago
8 0
The first part cannot be answered here without the diagram. However, I can tell you that the model he's building is 1/10 the size of the actual car. That means every measurement on the car is divided by 10 to get the model measurement.

The radius of the car wheel is 27 inches, so the diameter is 54 inches. Using what we know about the model, the correct proportions for the model wheel diameters would be 54 / 10, or 5.4, inches. Therefore, wheels with a diameter of 6 inches would not be in proportion with the model.
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Leokris [45]
The diameter of a circle that has a circumference of 30 inches would be around 9.5 inches- hope this helps!!
6 0
3 years ago
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34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below. L
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7 0
3 years ago
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What is the distance between (-1, 4) and (5, 4)?
andreev551 [17]

Answer:

6 units

Step-by-step explanation:

when you graph the coordinates on a graph they are straight side ways from each other. then you count how (0,4) is 1 unit, (1,4) is 2 units, (2,4) is 3 units, (3,4) is 4 units, (4,4) is 5 units, and (5,4) is 6 units.

therefore the answer is 6 units.

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4 0
4 years ago
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Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
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