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Keith_Richards [23]
3 years ago
11

A tank containing water up to a depth of 650 mm is stationary. Find the force exerted by fluid of specific gravity 0.55 on the s

ide of tank, width of tank is 1.5m. Ρ water = 1000 kg/m³:
Physics
1 answer:
timama [110]3 years ago
8 0

Answer:

3415.91 N

Explanation:

We know pressure, P at depth, h is P = ρgh where ρ = density of fluid = specific gravity × density of water = 0.55 × 1000 kg/m³ = 550 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water = 650 mm = 0.650 m

So, P = ρgh

= 550 kg/m³ × 9.8 m/s² × 0.650 m

= 3503.5 N/m²

Now pressure P = F/A where F = force on the side of tank and A = area of side of tank = depth of water × width of tank = 0.650 m × 1.5 m = 0.975 m²

So, F = PA

= 3503.5 N/m² × 0.975 m²

= 3415.913 N

≅ 3415.91 N

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To learn more about oscillations Please click on the given link:

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This is incomplete question Complete Question is:

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?

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