Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
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What is Escape Velocity ?</h3>
This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
- Mass (m) of the rocket 0.25 Kg
- Initial velocity u = 15 m/s
- Final Velocity v = 40 m/s
- Gravitational field intensity g = 9.8N/kg
The force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
Learn more about Escape Velocity here: brainly.com/question/13726115
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Answer:
Minimize the elevation or jump distance
Explanation:
The only action that minimizes, the impact force is to reduce as much as possible the height of the jump, the dog, ie the height from the jump point of the building. Since at the time of the jump its speed will increase every second at the rate of 9 [m/ s], that is this low effect of the gravitational acceleration of 9 [m/s^2]
where:
vf = final velocity [m/s]
g = gravity [m/s^2]
h = elevation [m]
As we can see while there is higher height, at a higher speed will impact the ground.
Answer: 20.73m/s
Explanation:
The question simply wants us to calculate the speed of the pitch. The speed will be calculated as:
= Distance/Time
where,
Distance = 85 meters
Time = 4.1 seconds
Speed = Distance/Time
Speed = 85/4.1
Speed = 20.73m/s
Therefore, the speed of the pitch is 20.73m/s.
Answer:
(C) Radiation
Explanation:
The weak nuclear forces causes radiation to form.
