Answer:
The final velocity of the wooden block is equal to 
Explanation:
Given that mass of bullet = 
Mass of wood = 
Initial velocity of bullet = 
Final velocity of bullet = 
Initial velocity of wood = o
Final velocity of wood = ![v_{w]](https://tex.z-dn.net/?f=v_%7Bw%5D)
Here momentum is conserved so initial momentum = final momentum
.
Upon substituting these values in above equation , we get
.
The _quamtum mechanical_ model of the atom states that an electron's exact location within an atom can not be determined, but its probable location can be estimated within a three-dimensional region called an atomic orbital and that an electron's properties within an orbital can only be described by a set of mathematical values called a quantum number.
The maximum height reached is 45.92 m
Answer:
44.3 m/s
Explanation:
a) Draw a free body diagram of the mass M. There are three forces:
Weight force mg pulling down,
Normal force N pushing perpendicular to the ramp,
and tension force T pulling parallel up the ramp.
Sum of forces in the parallel direction:
∑F = ma
T − Mg sin 30° = 0
T = Mg sin 30°
T = Mg / 2
Draw a free body diagram of the hanging mass m. There are two forces:
Weight force mg pulling down,
and tension force T pulling up.
Sum of forces in the vertical direction:
∑F = ma
T − mg = 0
T = mg
Substitute:
mg = Mg / 2
m = M / 2
M = 2m
b) Velocity of a standing wave in a string is:
v = √(T / μ)
T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N. Therefore:
v = √(49 N / 0.025 kg/m)
v = 44.3 m/s
Force = (mass) x (acceleration)
5 N = (9 kg) x (acceleration)
Divide each side
by 9 kg : 5 N / 9 kg = acceleration
Acceleration = (5/9) kg-meter/sec²-kg
= 0.555... m/s² .
