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Amiraneli [1.4K]
3 years ago
12

How to find the missing side of a triangle

Mathematics
2 answers:
Akimi4 [234]3 years ago
3 0

Answer:

All sides of a triangle should equal 180 degrees, so just add up the given sides and subtract them from 180

Step-by-step explanation:

USPshnik [31]3 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

16 / 2 = 8

a^2 + b^2 = c^2

8^2 + b^2 = 10^2

64 + b^2 = 100

<u>-64              -64</u>

b^2 = 36

square root 36

b = 6

so

x = 6

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

<em><u>-XxDeathshotxX</u></em>

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Which is the solution to the inequality y+15 &lt;3?
Paraphin [41]

To solve an equation or inequality, you can add the same value to both sides of the expression. Here, it is convenient to choose that value to be the opposite of the constant (+15) added to y, so that constant is replaced by zero.


  y + 15 - 15 < 3 - 15 . . . . . we have added -15 to both sides

  y < -12 . . . . . . . . . . . . . . . the result of simplifying. This is your solution.

6 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
Find the distance between the two points and simplest rational form (3,-4) (6,-7))
pychu [463]

Answer:

D = 3\sqrt{2}

Step-by-step explanation:

Given

(x_1,y_1) = (3,-4)

(x_2,y_2) = (6,-7)

Required

Determine the distance between the two points

Distance (D) is calculated as:

D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute values for x's and y's

D = \sqrt{(6 - 3)^2 + (-7 - (-4))^2}

D = \sqrt{(6 - 3)^2 + (-7 +4)^2}

D = \sqrt{(3)^2 + (-3)^2}

D = \sqrt{9+9}

D = \sqrt{18}

Express as 9 * 2

D = \sqrt{9*2}

Split:

D = \sqrt{9}*\sqrt{2}

D = 3*\sqrt{2}

D = 3\sqrt{2}

4 0
2 years ago
(6.253•10^-2)(7.112x10^3) in scientific notation
zlopas [31]

Answer:

4.4471336 * 10^2.

Step-by-step explanation:

(6.253•10^-2)(7.112x10^3)

= 6.253*7.112 * 10^-2*10^3

= 44.471336 * 10^1

= 4.4471336 * 10^2.

7 0
3 years ago
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