The compound interest formula is:
F = P * (1+i) ^ (n*t)
where:
F = future value
P = present value
i = r/n ; r = interest rate, n = number of times interest is compounded per year
t = number of years
Substituting:
F = 800 * ( 1 + .032/1 ) ^ (1*15) ; n=1 since compounded annually
F = 800 * ( 1 + 0.032) ^ (15)
F = 800 * ( 1.032) ^ 15
F = 800 * ( 1.60396711263693 )
F = 1283.17369010954
So there will be $1283.174 in the account.
a = 4, b = -21, c = -18
to keep from getting "mixed up", evaluate the discriminant first ...
b<sup>2</sup> - 4ac = (-21)<sup>2</sup> - 4(4)(-18) = 729
sqrt(729) = 27
x = (21 +/- 27)/8
x = -3/4, x = 6
since the discriminant is a perfect square, the original quadratic will factor ...
4x<sup>2</sup> - 21x - 18 = 0
(4x + 3)(x - 6) = 0
x = -3/4, x = 6
Answer:
.
Step-by-step explanation:
Given:
![cos\ \theta= \frac35](https://tex.z-dn.net/?f=cos%5C%20%5Ctheta%3D%20%5Cfrac35)
We need to find ![cos \ \frac{\theta}{2}](https://tex.z-dn.net/?f=cos%20%5C%20%5Cfrac%7B%5Ctheta%7D%7B2%7D)
Solution:
First we will find the value of
.
Now taking
on both side we get;
![\theta= cos^{-1} \ \frac{3}{5}\\\\\theta = 53.13](https://tex.z-dn.net/?f=%5Ctheta%3D%20cos%5E%7B-1%7D%20%5C%20%5Cfrac%7B3%7D%7B5%7D%5C%5C%5C%5C%5Ctheta%20%3D%2053.13)
Now we will find the
.
= ![\frac{53.13}{2} = 26.565](https://tex.z-dn.net/?f=%5Cfrac%7B53.13%7D%7B2%7D%20%3D%2026.565)
Now we will find
we get;
![cos \frac{\theta}{2}=cos\ 26.565 = 0.894](https://tex.z-dn.net/?f=cos%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%3Dcos%5C%2026.565%20%3D%200.894)
Hence
.