Ask question

Ask question

All categories

Nadusha1986 [10]

3 years ago

15

Solve in 5 + in 2x = 3

1 answer:

faltersainse [42]3 years ago

3 0

$\ln5+\ln 2x=3\\\\\ln10x=3\\\\e^3=10x\\\\x=\dfrac{e^3}{10}$

You might be interested in

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

a)

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

So

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b)

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

c)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0

3 years ago

Leam with an example

Nata [24]

Answer:

18 because 6 times 2 is twelve and 9 times 2 is 18... only if its direcrly proportional which it is

Step-by-step explanation:

pls mark brainliest it would really help me out

8 0

2 years ago

Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. Write an equation for

vivado [14]

Answer:

The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ .

Step-by-step explanation:

Given as :

The initial level of water in river = 34 feet

The rate of receding water level = 0.5 foot per day

Or, The rate of percentage of receding water level = 50 % per day

Let the level of water after d days = L

Now,

The level of water after d days = initial level of water × ( $(1-\dfrac{\textrm Rate}{100})^{Time}$

I.e L = 34 × ( $(1-\dfrac{\textrm 50}{100})^{d}$

∴ L = 34 × $(0.5)^{d}$

Hence The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ . Answer

5 0

3 years ago

What is the property to this problem ab+ac=(b+c)a

ryzh [129]

Answer:

Distributive Property of Multiplication

6 0

3 years ago

Read 2 more answers

I need help solving |5+2j|=9 please

V125BC [204]

$5 + 2j = 9 \\ j = 2$
$5 + 2j = - 9 \\ j = - 7$

3 0

3 years ago