Answer:
They bind to an allosteric site which induces a conformational change that increases the affinity of the enzyme's active site for its substrate. This increases the reaction rate.
Answer:
All the offsprings would be heterozygous purple colored flower
Explanation:
Given
Purple color flower is dominant over white color flower
Let the allele for purple color of flower be represented by "P"
and the allele for white color flower be represented by "p"
A pea plant that is homozygous purple-flowered is crossed with a pea plant that is white-flowered.
Genotype of homozygous purple-flower is "PP"
and Genotype of homozygous white-flower is "pp"
Cross between PP and pp produce the following offspring
PP * pp
Pp, Pp , Pp , Pp
All the offsprings would be heterozygous purple colored flower
The sequence of impulse through the cardiac conduction system starts from SA node passes to AV node to atrioventricular bundle fibers and finally to Purkinje fibers.
Heart is an organ that receives oxygenated blood form lungs and deoxygenated blood from different parts of body. Oxygenated blood is transported to different organs and deoxygenated blood is transported to lungs for oxygenation.
Now, to perform this transportation, the auricles and ventricles of heart contract and relax. In order to contract and relax, impulse generation is required, which begins at SA node or Sinoatrial node. It is also referred to as pacemaker of the heart. SA node contracts the atria and the impulse transfers to AV node or Atrioventricular node.
This is followed by transfer of impulse to atrioventricular bundle fibers which further passes it on to Purkinje fibres for ventricular contraction. Now the blood is sent to lungs and aorta as per it's oxygen status.
Learn more about cardiac conduction system -
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