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Likurg_2 [28]
3 years ago
8

Can someone help me out my grade are bad

Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

a. 0.4 and 0.5

b. 0.46

Step-by-step explanation:

i don't know if this right, so lmk

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Answer for a follow...
torisob [31]
24 bottles in total.....6 orange and 4 apple

probability of first picking an orange is 6/24 reduces to 1/4
probability of second picking an apple is 4/23

probability of both is 1/4 * 4/23 = 1/23
7 0
3 years ago
Help me! i have 20 minutes​
KIM [24]

Your on your own.. :/

5 0
3 years ago
En una sociedad participan 5 socios, colocando todos capitales iguales, lo unico que el primer socio estuvo 1 año y medio, el se
Mashutka [201]

Answer:

Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

Step-by-step explanation:

Dado que en una sociedad participan 5 socios, colocando todos capitales iguales, lo único que el primer socio estuvo 1 año y medio, el segundo 9 meses, el tercero 5 meses mas que el primero, el cuarto 1 año 7 meses y el quinto 2 años, para determinar cuánto le toca a cada socio de una utilidad de Q. 55,230.00 se deben realizar los siguientes cálculos:

Socio 1 = 1.5 años

Socio 2 = 0.75 años

Socio 3 = 1.916 años

Socio 4 = 1.583 años

Socio 5 = 2 años

Total = 1.5 + 0.75 + 1.916 + 1.583 + 2 = 7.75

Socio 1 =

7.75 = 100

1.50 = X

1.50 x 100 / 7.75 = X

19.35 = X

55,230 x 0.1935 = 10,690

Socio 2 =

7.75 = 100

0.75 = X

0.75 x 100 / 7.75 = X

9.68 = X

55,230 x 0.0968 = 5,345

Socio 3 =

7.75 = 100

1.916 = X

1.916 x 100 / 7.75 = X

24.72 = X

55,230 x 0.2472 = 13,655

Socio 4 =

7.75 = 100

1.583 = X

1.583 x 100 / 7.75 = X

20.43 = X

55,230 x 0.2043 = 11,285

Socio 5 =

7.75 = 100

2 = X

2 x 100 / 7.75 = X

25.81 = X

55,230 x 0.2581 = 14,255

Por lo tanto, Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

5 0
2 years ago
1
WARRIOR [948]
10 is the correct answer
4 0
2 years ago
Read 2 more answers
Karen runs a print shop that makes posters for large companies. It is a very competitive business. The market price is currently
kumpel [21]
AFC = FC / Quantity printed 

<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>

<span>ATC = TC / Quantity printed </span>

<span>where TC = FC + Variable C * Quantity printed </span>

<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>

<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>

<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
7 0
3 years ago
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