Answer:
y = 2 ( x − 1 ) ^ 2 + 2
Step-by-step explanation:
y = a ( x − h ) ^ 2 + k
where vertex is (h,k) = (1,2)
h=1, k=2
y = a ( x − 1 ) ^ 2 + 2
sub ( 3,10)
10 = a (3 - 1)^2 + 2
a=2
y = 2 ( x − 1 ) ^ 2 + 2
Answer:
0.9355
Step-by-step explanation:
What we will use here is conditional probability formula.
let A be the event that the plane departs on time
and B be the event that it arrives on time
P(A) = 0.87
P(B|A) = 0.93
P(B) = ?
P(A n B) = ?
Mathematically;
P(B|A) = P(B nA)/P(A)
0.93 = 0.87/P(A)
P(A) = 0.87/0.93
P(A) = 0.935483870967742
which is 0.9355 to four decimal places
Its letter A 3/20 i divided it
Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
