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Ede4ka [16]
3 years ago
4

Identify which equations have one solution, infinitely many solutions, or no solution.

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0
Here’s what I found online ...

Let's label them 1-6, for convenience.
1. 1 solution (a positive # of ys equaling a positive constant)
2. Infinitely many solutions (You get 0=0 if you completely simplify)
3. No solution (take out the 3z's; 2.5 doesn't equal 3.2)
4. Infinitely many solutions (take out the 3/4 x; 1.1+2 = 3.1)
5. No solution (take out the 4.5r; 0 doesn't equal 3.2)
6. 1 solution (x = 3 1/2)

Other than that, what are the equations? Do you have an attachment?
Bess [88]3 years ago
8 0

Having one solution, infinitely many solutions or no solution. These are called "Simultaneous Equations" or "Systems of Equation". They are for if you want to find the intercepts of both graphs.

Having only one solution, meaning that both graphs intercept each others at only one single ordered pair or only a single (x,y).

Having infinite many solutions, meaning that both graphs are same and intercept infinitely (For example if you have to solve 2 quadratic equations and find the intercepts. Given that both quadratic equations are the same equations. For example, x^2 = x^2 as you'll get x^2-x^2 = 0, 0=0. Notice that when it's 0=0. That means the equation is true for all real numbers (Because x^2 = x^2 which is always true.)

Having no solution, meaning that the graph doesn't intersect another graph. When you do the equations, you might expect something like 2 = 0. For example,

x+1=x+6\\x+1-x-6=0\\0-5=0\\0=5

Notice how 0 = 5 is false. If the equation is false, that means the equation is not true for all real numbers. So no matter what x values you are going to substitute in, it won't be true (considering both graphs don't intercept each others.)

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if the length of a rectangle is increased by 30 percentage and the width of the same rectangle is decreased by 30 what is the af
LUCKY_DIMON [66]

Answer:

The area will decrease by 9%.

Step-by-step explanation:

The area of a rectange is given by the formula below.

\boxed{\text{Area of rectangle}= \text{length}×\text{width}}

Let the original length and width of the rectangle be L and W respectively.

Start by finding the original area:

<u>Original </u><u>dimensions</u>

Length= L= 100%L

Width= W= 100%W

Original area= LW

Let's find the dimensions of the new rectangle in terms of L and W.

<u>New dimensions </u>

Length= (100% +30%)L= 130%L

Width= (100%-30%)W= 70%W

New area

=  \frac{130}{100} L  \times \frac{70}{100} W

=  \frac{91}{100} LW

= 91% LW

Comparing the new area with the original area:

100% LW- 91% LW= 9% LW

∴ The area will decrease by 9%.

*Note that percentage is equivalent to dividing a number by 100.

4 0
2 years ago
The ratio between 7 in and 10 ft
motikmotik
7:120 i think thats what its asking
3 0
4 years ago
Multiply.
prohojiy [21]

Answer:

D. 3x² + 19x - 14

Step-by-step explanation:

Use FOIL to find the answer.

First: x * 3x = 3x²

Outer: -2 * x = -2x

Inner: 3x * 7 = 21x

Last: 7 * -2 = -14

Form the equation:

3x² - 2x + 21x - 14

Combine like terms.

3x² + 19x - 14

8 0
3 years ago
44735758 x 46639756-435333 divided by 48883 = what pls help will give brainleist
Lera25 [3.4K]

Answer:

2.0864648e+15

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Molly bought a large basket of 6060 apples. When she got home, she found 44 rotten ones. If she goes back and buys 200200 more a
Flauer [41]

Answer: 13

Step-by-step explanation:

This is the correct question:

Molly bought a large basket of 60 apples. When she got home, she found 4 rotten ones. If she goes back and buys 200 more apples, how many rotten apples would she expect there to be?

From 60 apples, there are 4 rotten apples. This gives a fraction of:

= 4/60

= 0.06667

Therefore, when she buys 200 apples, tge number of rotten ones expected will be:

= 0.06667 × 200

= 13.334

= 13 approximately

4 0
3 years ago
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