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KiRa [710]
3 years ago
9

Write an expression that is equivilant to 5(6+y)

Mathematics
2 answers:
makkiz [27]3 years ago
6 0

Answer:

6(5+y) or (30+y)

Step-by-step explanation:

You can just switch around the variables and numbers but keep the equation the same or simplify

Dmitry [639]3 years ago
5 0

Answer: 30+5y

Step-by-step explanation: Which is simplifying

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2

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8 0
4 years ago
50% of babies are born female Oliver wants to find the probability that 20 or more of the 50 babies born today were female if we
jarptica [38.1K]

Solution:

Number of babies which are female = 50%=\frac{1}{2}

So, if Population of 50 is considered , and 50% of population is female then  out of 25 must be female.

Population of female can't exceed 25.

Probability of an event = \frac{\text{Total favorable outcome}}{\text{Total Possible outcome}}

 Probability that 20 or more of the 50 babies born today were female

    =  _{20}^{50}\textrm{C}\times [\frac{1}{2}]^{20} \times [\frac{1}{2}]^{30}+_{21}^{50}\textrm{C}\times [\frac{1}{2}]^{21} \times [\frac{1}{2}]^{29}+_{22}^{50}\textrm{C}\times [\frac{1}{2}]^{22} \times [\frac{1}{2}]^{28}+_{23}^{50}\textrm{C}\times [\frac{1}{2}]^{23} \times [\frac{1}{2}]^{27}+_{24}^{50}\textrm{C}\times [\frac{1}{2}]^{24} \times [\frac{1}{2}]^{26}+ _{25}^{50}\textrm{C}\times [\frac{1}{2}]^{25} \times [\frac{1}{2}]^{25}

Simulation of the Above Situation

If we use a double sided coin and a sign heads us females and Tails as males,Toss the coin 50 times , number of times Heads comes shows number of females born and number of times tails appears shows Population of men.

It may not happen that Number of heads =Number of tails if we toss the coin 50 times.So if number of tosses increases the chances are more likely that , number of heads= Number of tails. But for above problem we just have to toss coin 50 times only, that is

Number of males = Number of females


8 0
4 years ago
Read 2 more answers
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