All categories

3 years ago

If you have $.10 on your debit card can you buy a measuring tape at the hardware store yes or no

Mathematics

1 answer:

ollegr [7]3 years ago

8 0

No you can’t because a measuring tape at a hardware store is either $5 or $10

You might be interested in

What is the answer for this question 5 + (x^2 - xy) - 4

zzz [600]

Answer: x^2−xy+1

Step-by-step explanation:

simplify:

5+x^2−xy−4

5+x^2+−xy+−4

Combine Like Terms:

5+x^2+−xy+−4

(x^2)+(−xy)+(5+−4)

x^2+−xy+1

3 0

2 years ago

Please help!!!! Tell me whether it’s a equation or not pleasr

goldfiish [28.3K]

This answer is a equation, my teacher told me this

3 0

3 years ago

What is 7.505 as a fraction

klemol [59]

1501 / 200

this is what i looked up an got

4 0

2 years ago

in which place is the digit in the numbers 5,341 that would be changed to form 5,841? how do the values of the two numbers compa

Akimi4 [234]

The changed digit is the third to the left of the decimal point, so is in the hundreds place.

The value of 8 hundred is 5 hundred more than the value of 3 hundred. The second number is 500 more than the first.

7 0

3 years ago

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me

Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

$\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286$

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is $P(X = 2)$ . So:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073$

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0

3 years ago