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Amanda [17]
3 years ago
8

100 points! Please help asap! Look at the picture attached. My teacher said that both 1 and 2 are neither can someone explain wh

y they are neither? Correct answers will get brainliest!

Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

Your teacher is right, there is not enough info

Step-by-step explanation:

<h3>Question 1</h3>

We can see that RS is divided by half

The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS

So P is not on the perpendicular bisector of RS

<h3>Question 2</h3>

We can see that PD⊥DE and PF⊥FE

There is no indication that PD = PF or ∠DEP ≅ FEP

So PE is not the angle bisector of ∠DEF

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2 years ago
10. 2x + 7y = 1<br> 2x - 4y = 12<br> Solve for y
adoni [48]

Answer:

The solution for y = -1.

Step-by-step explanation:

Given:

2x\ +\ 7y\ =\ 1    ....(1)

2x\ -\ 4y\ =\ 12  ....(2)

So, to solve for y, first we solve for x in equation (2):

2x-4y=12

⇒2x=12+4y

Dividing both sides by 2,

⇒x=6+2y            

Now, substituting the value of x  in equation (1):

2x+7y=1

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⇒11y=1-12

⇒11y=-11

Dividing both sides by 11,

⇒y=-1

Therefore, the solution for y = -1.

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