Question

6. Two linear equations are shown in the graph.

Answer 1

Answer:

(3,3)

Step-by-step explanation:

Linear equations of lines are given in the form:

y = mx + b;

where m is the slope of the line, b is the y intercept and x, y are variables.

From the graph, we can see that line 1 passes through (0,6) and (6,0) while line 2 passes through (0, 1) and (6, 5).

The equation of line 1 is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-6=\frac{0-6}{6-0} (x-0)\\\\y=-x + 6\ \ \ (1)$

The equation of line 2 is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-1=\frac{5-1}{6-0} (x-0)\\\\y=\frac{2}{3}x + 1\ \ \ (2)$

Solving equation 1 and 2 simultaneously by subtracting equation 1 from 2 gives:

(5/3)x - 5 = 0

(5/3)x = 5

x = 3

Put x = 3 in equation 1:

y = -3 + 6 = 3

Therefore the two lines meet at (3, 3).