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Vlad1618 [11]
3 years ago
14

IM IN A TEST NOW WILL AWARD BRAINLIEST!!!!!

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

The product has decreased by 80 %

<em><u>Solution:</u></em>

The product of the original numbers: xy

One number is decreased by 75 %

Let x be the number decreased by 75 %

new number = x - 75 % of x

new\ number = x - 75 \% \times x\\\\new\ number = x(1-75 \%)\\\\new\ number = x(1-\frac{75}{100}) = x(1-0.75) = 0.25x

Another number is decreased by 20 %

Let y be the number decreased by 20 %

new number = y - 20 % of y

new\ number = y - 20 \% y\\\\new\ number = y(1-20 \%)\\\\new\ number = y(1-\frac{20}{100}) = y(1-0.2) = 0.8y

<em><u>Now the product is given as:</u></em>

product = 0.25x \times 0.8y = 0.2xy

<em><u>Now we have to find the percent decreased</u></em>

Subtract new product and original product and then divide by original product . Multiply the result by 100 to get percentage

percent\ decrease = \frac{0.2xy - xy}{xy} \times 100\\\\percent\ decrease = \frac{-0.8xy}{xy} \times 100 = -0.8 \times 100 = -80

Here negative sign denotes decrease

Thus the product has decreased by 80 %

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