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gizmo_the_mogwai [7]

3 years ago

5

In this equation, is (1, 5) a solution? *

1 answer:

monitta3 years ago

8 0

Answer:

No (1,5) is not a solution

Step-by-step explanation:

if you try to solve this equation with the (1,5), you lay it out like 5 = 1/4 * 1 - 7. It turns into 5 = 1/4 - 7, because 1 times anything is that same number. Then you have to add 7 to both sides so that it cancels out on the right and you get 12 on the left. So you end up with the equation 12 = 1/4. This equation is not true, so therefore (1,5) is not a solution. Hope this helps :)

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3 years ago

L=U²A divided by (A+B)² make A the subject of formular

nikklg [1K]

Answer:

A = [- 2Bl + U^2 +/- √((2BL - U^2)^2 - 4B^2L^2) ] / 2L

Step-by-step explanation:

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Using the quadratic formula

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3 years ago

Help will up-voter!

harina [27]

<h2>Steps:</h2><h3>A.</h3>

For this, plug 4 into the x variable (since 4 is in the x variable of g(x)) and solve as such:

$g(4)=\frac{1}{2}*4+5\\\\g(4)=2+5\\\\g(4)=7$

<u>Your final answer is g(4) = 7.</u>

<h3>B.</h3>

For this, it's a similar process as A, but you are plugging -10 into the x variable and solving:

$g(-10)=\frac{1}{2}*(-10)+5\\\\g(-10)=-5+5\\\\g(-10)=0$

<u>Your final answer is g(-10) = 0</u>

<h3>C.</h3>

Similar process as before, but you are plugging 0 for x to solve:

$g(0)=\frac{1}{2}*0+5\\\\g(0)=0+5\\\\g(0)=5$

<u>Your final answer is g(0) = 5.</u>

7 0

2 years ago