First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
solving a linear equation we conclude that the value of x must be 6.
<h3>
How to find the value of x?</h3>
On the statement we have the relations:
AB = BC
BC = CD
For the transitive property, then we have that:
AB = CD
Replacing the equations in the image, we get:
2x + 1 = 4x - 11
Solving this linear equation for x we get:
1 + 11 = 4x - 2x
12 = 2x
12/2 = x
6 = x
So yes, solving that linear equation we conclude that the value of x must be 6.
Learn more about linear equations:
brainly.com/question/1884491
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According to my calculations 1.8e9
Complementary angles add up to 90o.
The complement of 21 is 90 - 21 = 69
