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lara31 [8.8K]
3 years ago
14

En un triángulo obtusángulo, uno de los ángulos mide 20° mas que el otro. El tercer ángulo, mide el doble que el mayor de los do

s que hemos citado. ¿?Cuánto miden los ángulos de dicho triángulo
Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

La medida del primer ángulo es 30°, la medida del segundo ángulo es 50° y  el tercer ángulo mide 100°.

Step-by-step explanation:

Siendo "x" el valor de un ángulo del triángulo obtusángulo, sabes que uno de los ángulos, llamado segundo ángulo, mide 20° más que el primero. Este segundo ángulo se representa como x + 20°.

Además, un tercer ángulo mide el doble que el mayor de los dos, que en este caso es el ángulo cuya expresión es x + 20°. Por lo que el doble de este será 2*(x + 20)°, que será la medida del tercer ángulo.

Teniendo en cuenta que la suma de los ángulos interiores de un triángulo es 180°. Entonces, es posible sumar los valores de cada uno de los ángulos e igualarlos a 180°:

x + x + 20° + 2*(x + 20°) = 180°

Resolviendo:

x + x + 20° + 2*x + 2*20° = 180°

x + x + 20° + 2*x + 40° = 180°

4*x + 20° + 40° = 180°

4*x + 60° = 180°

4*x = 180° - 60°

4*x = 120°

x = 120° ÷ 4

x = 30°

Entonces, la medida del primer ángulo es 30°. El segundo ángulo es calculado como x + 20° = 30° + 20° = 50° mientras que  el tercer ángulo es 2*(x + 20°) = 2*(30° + 20°) = 2*(50°) = 100°

<u><em>La medida del primer ángulo es 30°, la medida del segundo ángulo es 50° y  el tercer ángulo mide 100°.</em></u>

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