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goldenfox [79]
3 years ago
9

Hey! Can someone help me find the value of x please!!!!! it's my last question!​

Mathematics
2 answers:
Margaret [11]3 years ago
8 0

Answer:

3x!

Step-by-step explanation:

Since the sides are the same (marked with the lines on the side) the 2 angles are also the same! :D

Pavel [41]3 years ago
4 0

Answer:

is this math

Step-by-step explanation:

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10Hello, can you help me with this? How much is 5 raised to 5?​
vesna_86 [32]

Answer:

A 5 by 5 Power in Trust is a clause that lets the beneficiary make withdrawals from the trust on a yearly basis. The beneficiary can cash out $5,000 or 5% of the trust's so-called fair market ...

Step-by-step explanation:

5^5

=5*5*5*5*5

=5^5

=3125

6 0
3 years ago
Solve the inequality. –6 < 2x – 4 < 4
Darya [45]

Answer:

–1 < x < 4

Step-by-step explanation:

Let's solve your inequality step-by-step.

−6<2x−4<4

−6+4<2x−4+4<4+4(Add 4 to all parts)

−2<2x<8

(−2 /2) < (2x /2 )<  (8 /2)

(Divide all parts by 2)

−1<x<4

6 0
3 years ago
What are the center and radius of the circle defined by the equation x^2 y^2-6x 4y 4=0?
Kazeer [188]
Please rewrite this equation of the circle correct with signs of minus or plus 
6 0
3 years ago
Write the expression that represents length in terms of width for this problem
raketka [301]
Assuming you are talking about the rectangle, 

width = area/lenght
5 0
3 years ago
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
4 years ago
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