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3 years ago

How do you solve -1/12 - (-11/12)

1 answer:

7 0

-1/12 - (-11/12) would change into -1/12 + 11/12 because a double negative (bold print) would become a positive. The answer to the new problem would be 10/12 or 5/6 (depending on if it says to simplify).

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Annie has 4 1/2 feet of rope what is the greatest number of 3/4 foot pieces that annie can cut from the rope

Viefleur [7K]

Answer:

Step-by-step explanation:

4 1/2 divided by 3/4 is 6. so 6 pieces

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2 years ago

If f(x) = 2x + 3 and g(x) = 3x - 9, find (f + g)(x).

coldgirl [10]

Answer:

5x-6

Step-by-step explanation:

f(x) = 2x + 3

g(x) = 3x - 9

f(x) + g(x) = 2x + 3 + 3x-9

= 5x-6

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2 years ago

I need these done as quick as possible and i have no clue what to do.

Korvikt [17]

Answer:

1. y = 4

2. x = 10

3. n = 6

4. m = 4

5. h = 2

Step-by-step explanation:

Hope this helps!!

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2 years ago

Read 2 more answers

dibuja un triangulo de catos de 15cm, 8cm. al unir sus puntos medios resulta un triangulo semejante a este

marshall27 [118]

Answer:

Step-by-step explanation:

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3 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

2 years ago