Answer:
a) The probability that the airline will lose no bags next monday is 0.1108
b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227
c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2
Step-by-step explanation:
The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

a)

The probability that the airline will lose no bags next monday is 0.1108.
b) Note that
. And

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.
c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.
Answer:
Hey there!
I think your answer would be unimodal skewed. This graph only has one maxima, thus it can't be bimodal. However, it's not symmetric, meaning that it is skewed.
Hope this helps :)
Answer:

Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs
For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:

and solving for b we got:

And then we can conclude that she earns 60 for each TV
Step-by-step explanation:
For this case we can set a linear model like this:

Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs
For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:

and solving for b we got:

And then we can conclude that she earns 60 for each TV
Answer:
.0000111
Step-by-step explanation:
move the decimal five places to the left because the 5 is negative