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3 years ago

Find the slope of the lines shown in the graph

Mathematics

1 answer:

Lunna [17]3 years ago

4 0

Red line: -2/3
Blue line: 2/1
Black line: 1/3

Sorry if it’s wrong, but I went be an through my math notes to try and figure it out for you.

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2. Find the value of the expression 21 – 2a if a = 3.

timama [110]

Answer:

Step-by-step explanation:

we just substitute the value of "a" given in the above expression we get

21-2(3)

21-6=15

7 0

3 years ago

Read 2 more answers

Find the value of x to make the following expression true.<br> 3x=729

ohaa [14]

The value of x is 243
(correct me if wrong)

6 0

3 years ago

Read 2 more answers

ycow [4]

Answer:

45 pages in 1 hour

Step-by-step explanation:

Find the unit rate by dividing the number of pages by the number of hours

135/3

= 45

This means he can read 45 pages in 1 hour.

The unit rate is 45 pages in 1 hour.

8 0

2 years ago

Rewrite the equation below into standard form. 2y=3x+12

olasank [31]

Standard form: 3x−2y=−<span>12 </span>

3 0

3 years ago

Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

$P(X \geq 2) = 0.93803$

5 0

2 years ago