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SIZIF [17.4K]
3 years ago
7

Nick mowed about 3/5 of the school lawn yesterday. He mowed another 1/4 of the lawn this morning. How much is left to mow?

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0
Soo 1/4 is equal to 5/20 and 3/5 is equal to 12/20 and you add the two sooo 17/20 but you wanna find how much is left to mow soo 1 - 17/20 is 3/20
So the answer is
3/20
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2) \left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)   \tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}

3) \left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)    

4) \left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)    \sin^{2}A+\cos^{2}A = 1

5) \frac{1}{\sin^{2}A\cdot \cos^{2}A}

6) \frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}    \sin^{2}A+\cos^{2}A = 1

7) \frac{1}{\sin^{2}A-\sin^{4}A} Result

Step-by-step explanation:

Let \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right), we proceed to prove the trigonometric expression by trigonometric identity:

1) \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right) Given

2) \left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)   \tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}

3) \left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)    

4) \left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)    \sin^{2}A+\cos^{2}A = 1

5) \frac{1}{\sin^{2}A\cdot \cos^{2}A}

6) \frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}    \sin^{2}A+\cos^{2}A = 1

7) \frac{1}{\sin^{2}A-\sin^{4}A} Result

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Hello There!

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