Answer:
109.2-23.6 = 85.6
Step-by-step explanation:
use bodmas
B=bracket
O=of or multiplication
D=division
M=multiplication
A=addition
S=subtraction
so when you are opening a bracket you multipli the number in the bracket with the one outside the bracket
I.E
4×27.3=109.3
4×5.9=23.6
109-23.6=85.6
Answer:
Step-by-step explanation:
Answer:
256.8
Step-by-step explanation:
the tenths place is the first number after the decimal.
Answer:
![y\in (-\infty ,5]](https://tex.z-dn.net/?f=y%5Cin%20%28-%5Cinfty%20%2C5%5D)
Step-by-step explanation:
In this problem, we need to write "Twenty times y is at most 100 in interval notation
".
20 times y means, 20y
Atmost means an inequality which is 
ATQ,
i.e.
We can also write it as :
Hence, the required interval notation is .
Answer: 18x^3-9x^2+21x
Solution:
3x(6x^2-3x+7)=
Applying the distributive property in the multiplication to eliminate the parentheses:
(3x)(6x^2)+(3x)(-3x)+(3x)(7)=
(3*6)x^(1+2)+3*(-3)x^(1+1)+(3*7)x=
18x^3-9x^2+21x
