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Tasya [4]
3 years ago
7

HELPPPPP: The average high temperatures each month in Dallas, Texas are shown in the chart. What value represents the 3rd 3rd qu

artile for this data?
Mathematics
2 answers:
Sloan [31]3 years ago
5 0

Answer: 79

Step-by-step explanation:

Line up the numbers from least to greatest. 39, 42, 44, 51, 55, 62, 66, 72, 77, 81, 94, 86 Then find the Median. Look at the upper part of the data set and from there find the 3rd quartile.

Natasha2012 [34]3 years ago
5 0

Answer:

79 i did it and got it right sorry for late response

Step-by-step explanation:

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Fantom [35]

Answer:

110

Step-by-step explanation:

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The expression 1.5y — 6 factored is
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Y=4 is the answer to your question
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According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are re
Luda [366]

Answer:

The questions asked are

If you randomly select 4 peanuts

1. Compute the probability that exactly three of the four M&M’s are brown

2. Compute the probability that two or three of the four M&M’s are brown.

3. Compute the probability that at most three of the four M&M’s are brown.

4. Compute the probability that at least three of the four M&M’s are brown.

Step-by-step explanation:

Given the following information

Brown=12%. P(B)=0.12

Yellow=15%. P(Y)=0.15

Red=12%. P(R), =0.12

Blue=23%. P(B) =0.23

Orange, =23%. P(O) =0.23

Green=15%. P(G)=0.15

Question 1.

They are independent events

If there are exactly three brown and the last is not brown

P(B n B n B n B')

P(B)×P(B)×P(B)×P(B')

0.12×0.12×0.12×(1-P(B))

0.001728×(1-0.12)

0.001728×0.88

0.00152.

0.152%

2. If two or three are brown

I.e we are going to two brown and two none brown or three brown and one not brown. (P(B)×P(B)×P(B')×P(B'))+ (P(B)×P(B)×P(B'))

(0.12×0.12×0.88×0.88)+(0.12×0.12×0.12×0.88)

0.0112+0.00152

0.0127

1.27%

3. At most three brown out of four then we are going to have

BBBB', BBB'B', BB'B'B', B'B'B'B'

These are the cases of at most three brown.

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B')×P(B') + P(B)×P(B')×P(B')×PB')+ P(B')×P(B')×P(B')×P(B')=

0.12×0.12×0.12×0.88+ 0.12×0.12×0.88×0.88+ 0.12×0.88×0.88×0.88+ 0.88×0.88×0.88×0.88=0.694

0.694

69.4%

4. At least 3 brown out of four selection

I.e BBBB', BBBB

These are the two options

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B)×P(B)=

0.12×0.12×0.12×0.88 + 0.12×0.12×0.12×0.12

0.001728

0.173%

4 0
3 years ago
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1/3n-7/12=-3/8 n=5/72 n=-5/72 n=5/8 n=-2 7/8
prisoha [69]

Given the equation;

\frac{1}{3}n-\frac{7}{12}=-\frac{3}{8}

To solve, let us multiply through by the least common multiple of the the denominator of the three fractions wich is 24;

3 0
1 year ago
If a central angle measures 25, then the measure of its intercepted arc is
borishaifa [10]
Medida do angulo central = medida do arco interceptado
arco = 25º e ângulo central = 25º
7 0
3 years ago
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