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3 years ago

12

What is 6/8 * 4/6? Please answer this!!!

1 answer:

irina1246 [14]3 years ago

3 0

6*4=24
8*6=48
24/48=4/8=1/2
I hope this helps;)

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Cho tập hợp S gồm 100 số tự nhiên từ 1 đến 100 .Chọn ngẫu nhiên 2 số từ tập hợp S , tính xác suất để tích 2 số chia hết cho 5

nevsk [136]

Answer:

mjhghjmkvgk,lm

Step-by-step explanation:

4 0

2 years ago

Here is a probability scale

xxMikexx [17]

Answer:

a) e

b) c

c) a

Step-by-step explanation: Look at the number line. 0 shows that it has no probability while C is at 1/2 showing that it could be half-half. Then you can see one under E which means it is bound to happen.

5 0

3 years ago

Am i doing this right????

Anna35 [415]

You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
√ 36 + 100 =
√136

√34² + √136² =√170²
34 + 136 = 170
170 = 170

3 0

3 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

<u>Answer:</u>

a) 3.675 m

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

Please help asap and I will give Brainliest

Natasha_Volkova [10]

Option A. 5/8 is the correct answer.

Step-by-step explanation:

Square root by factorization will be used to solve this question.

Given

$\sqrt{\frac{25}{64}}$

The square root can be applied to numerator and denominator separately

$=\frac{\sqrt{25}}{\sqrt{64}}$

Factorization

$=\frac{\sqrt{5*5}}{\sqrt{2*2*2*2*2*2}}\\=\frac{\sqrt{5^2}}{\sqrt{2^2*2^2*2^2}}\\=\frac{5}{2*2*2}\\=\frac{5}{8}$

Hence,

Option A. 5/8 is the correct answer.

Keywords: Square roots, factorization

Learn more about square root at:

#LearnwithBrainly

3 0

3 years ago