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JulsSmile [24]
3 years ago
9

Write an equation in point-slope form and in slope-intercept form for the line that passes through the given point

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

point-slope:x-y+3

slope-intercept: y=x-3

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How can you do subtract three Digit numbers
Aleonysh [2.5K]
First off, you have to subtract the 3rd number, then carry the number if so, then do the same to the second and first number, did i help in any way?
4 0
3 years ago
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If zeba were younger by 5 years than what she really is then the square of her age would have been 11 more than five times her a
RSB [31]

Answer:

14 years old

Step-by-step explanation:

<u>Define the variable</u>

Let x be the actual age of Zeba (in years).

<u>Create an equation</u> using the give information and the variable x:

(x - 5)^2=5x+11

To find Zeba's age now, <u>solve the equation for x</u>.

Expand the brackets:

\implies x^2-10x+25=5x+11

Subtract 5x from both sides:

\implies x^2-10x+25-5x=5x+11-5x

\implies x^2-15x+25=11

Subtract 11 from both sides:

\implies x^2-15x+25-11=11-11

\implies x^2-15x+14=0

<u>Factor the found quadratic</u>

To factor a quadratic in the form ax^2+bx+c<em>, </em>find two numbers that multiply to ac and sum to b, then rewrite b as the sum of these two numbers:

\implies x^2-14x-x+14=0

Factor the first two terms and the last two terms separately:

\implies x(x-14)-1(x-14)=0

Factor out the common term (x - 14):

\implies (x-1)(x-14)=0

Apply the <u>zero product property</u>:

\implies (x-1)=0 \implies x=1

\implies (x-14)=0 \implies x=14

Therefore, Zeba's age now is either 1 or 14 years.

As the question states "If Zeba were younger by 5 years" then 1 must be an <u>extraneous solution</u> since 1 - 5 = -4 and Zeba cannot be -4 years old.

Therefore, Zeba's age now is 14 years old.

<u>Check</u>

Given the actual age of Zeba is 14 years old.

Therefore, If Zeba were younger by 5 years, she would be 9 years old as:  14 - 5 = 9

The square of 9 is:  9² = 81.

5 times her actual age:  5 × 14 = 70

81 is 11 more than 70, hence verifying that her <u>actual age is 14 years old</u>.

Learn more about quadratic equations here:

brainly.com/question/27956741

brainly.com/question/27947331

5 0
1 year ago
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PLSSS HELP IF YOU TURLY KNOW THISS
Vlada [557]

Answer:

The missing exponent is 15.

Step-by-step explanation:

<h2><u><em>Brainliest Please!</em></u></h2>
4 0
2 years ago
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Is this formula correct?
Flura [38]

Hey there!!

Volume of a cone : πr²h/3

Where, πr²h is the volume of a cylinder.

Hence,

V cone = V cylinder / 3

Hence,

The above mentioned formula is wrong/false.

Hope my answer help!!

6 0
3 years ago
1. I am a three-digit number. My tens digit is 3 more than my
Tems11 [23]

Answer:

1. 474

2. 397

Step-by-step explanation:

1. If the three-digit number is xyz, then y = z + 3.

When rounded to the nearest ten and reduced by 320, the result is 150.  150 + 320 = 470, so x = 4.  y = 6 if z ≥ 5, and y = 7 if z < 5.

So the number is either 463 or 474.  463 doesn't round to 470, so the answer is 474.

2. If the three-digit number is xyz, then z = x + 4.  y is the largest of the three digits; since all the digits are odd, y is either 5, 7, or 9.  So z is either 5 or 7, and x is either 1 or 3.

When rounded to the nearest hundred and reduced by 100, the result is 300.  100 + 300 = 400, and y > 5, so xyz is rounded up to 400, which means x = 3.  So z = 7 and y = 9.

The answer is 397.

6 0
3 years ago
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