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3 years ago

Please help me:

Mathematics

1 answer:

lora16 [44]3 years ago

6 0

Answer:

6 units

Step-by-step explanation:

This coordinate is a three dimensional coordinate, which involves positive and negative x,y, and z axis.

The y axis is from left to right, i.e from negative to positive.

So 6 unit left is = -6 but it explains moving left .

Thank you

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According to scientific research, the probability that a person between the ages of 20 and 25 having high blood pressure, is onl

boyakko [2]

Answer:

<h2>The probability is ${\frac{83}{100} }^9 \times \frac{17}{100}$ + ${\frac{83}{100} }^8 \times {\frac{17}{100} }^2$ + ${\frac{83}{100} }^{10}$ .</h2>

Step-by-step explanation:

The probability of having high blood pressure is 17%.

We need to find the probability of 2 or fewer have high blood pressure.

Possibility 1: No one have high blood pressure.

The probability is ${\frac{100 -17}{100} }^{10} = {\frac{83}{100} }^{10}$ .

Possibility 2: Only one have high blood pressure.

The probability is ${\frac{83}{100} }^9 \times \frac{17}{100}$ .

Possibility 3: 2 among the 10 have the high blood pressure.

${\frac{83}{100} }^8 \times {\frac{17}{100} }^2$ .

Any of the possibilities can happen.

Hence, the required probability is ${\frac{83}{100} }^9 \times \frac{17}{100}$ + ${\frac{83}{100} }^8 \times {\frac{17}{100} }^2$ + ${\frac{83}{100} }^{10}$ .

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (

Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138 (1)

The second equation in the unknowns is

3B + 5N = 71 (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===> 40B + 30N = 690 (3)

Multiplying (2) by 6 ===> 18B + 30N = 426 (4)

(3) - (4) eliminates the N variables and yields

22B = 264 ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==> 36 + 5N = 71 ==> 5N = 71-36 = 35 ==> N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0

2 years ago

Jared has some quarters and dimes that total $5.50. If he has 8 more quarters that dimes, how much dimes does Jared have?

MAXImum [283]

Answer: 10 dimes

Solve using system of equations.
q=number of quarters and d=number of dimes
.25q+.10d=5.50 because the total of dimes and quarters is $5.50
8+d=q because there are 8 more quarters than dimes
substitute 8+d for q into the first equation to get .25(8+d)+.10d=5.50
then simplify
2+.35d=5.50
.35d=3.50
d=10 he has 10 dimes

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4 years ago

Javier has basket of oranges and apples. The number of oranges is more than twice the number of apples in the basket. The differ

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Answer:

Its actually one solution it is solvable and only has one solution

Step-by-step explanation:

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3 years ago