Eog prep-?? I tried to solve it didn't work out
2 answers:
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There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
' in a right triangle, '
' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.
So, for this setup:
Now, we solve for x:
So, answer is 3.4
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
So, for this setup:
Now, we solve for x:
So, answer is 3.4