There are 
of each suit in a deck of 
cards.
This means the probability of drawing a diamond card is 
. You can divide the numerator and denominator each by to simplify. 
Since there are the same number of clubs as there are diamonds, the probabilities are the same.
In this case, we must use trigonometry to find the value of x:
Thus the value of x rounded to the nearest tenth is <u>8.2</u>
<u></u>
Hope that helps!
Step-by-step explanation:
The above given statements can be written as decimals by first writing both quantities in a statement in the same unit.
1. $6.00 to 95 cents:
This is same as $6.00 : 95 cents = \frac{6.00}{95}956.00
Convert $6 .00 to cents to make both quantities be in the same unit.
$1 = 100 cents
$6.00 = 6*100 = 600 cents
\frac{600}{95} = 6.3295600=6.32 (to 2 d.p)
2. 3 hours to 35 minutes:
Convert 3 hours to 35 mins
1 hr = 60 mins
3 hrs = 3*60 = 180 mins
180mins : 35 mins = \frac{180}{35} = 5.14180mins:35mins=35180=5.14 (2 d.p)
3. 42 inches to 2 feet:
Convert 2 ft to inches
1 ft = 12 inches
2ft = 2*12 = 24 inches
42 in:24 in = \frac{42}{24} = 1.7542in:24in=2442=1.75
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
Answer:
I think its......false (I tried)
Step-by-step explanation:
