The numbers are "x" and "y", therefore, we suggest this system of equations:
x-y=14
xy=1800
We can solve by substitution method.
x=14+y
(14+y)y=1800
14y+y²=1800
y²+14y-1800=0
Now, we solve this square equation:
y=[-14⁺₋√(196+7200)] / 2=(-14⁺₋86)/2
We have two solutions:
y₁=(-14-86)/2=-50 ⇒x=14+y=14-50=-36
y₂=(-14+86)/2=36 ⇒x=14+y=14+36=50
Answer: we have two solutions:
Solution1: The first number is -36 and the other number is -50
Soltuion2: The first number is 50 and the other number is 36
To draw a histogram, you need two axes. The horizontal axis is the day and the vertical axis is the number of text messages. For the first day, there are 20 text messages. This is represented by a bar starting from the horizontal axis labeled Day 1 going up to the point where the vertical axis indicates 20 text messages. This is done for the rest of the data. Afterwards, a line is drawn from the vertex of the axes connected to the top of the first bar. Then from the top of the first bar, a line connects it to the top of the next bar. This is done for all the bars before producing a histogram.
Answer:
3.216%
Step-by-step explanation:
This bond sells at a higher price or value, which means that its coupon is bogus of market interest rate. Therefore, the minimum yield rate that accounts for the possibility of the bond being called is calculated at the earliest possible call date. Let say exactly 15 years from the date of purchase, because that would be the most disadvantageous date for the bondholder for the call to occur.
The minimum semiannual yield:
j= i²/2
i² = 2j
which therefore satisfies the expression below for the worst possible case scenario yield:
1722.25 = 0.04*1100*
+
Also, with the use of a financial calculator (making sure that the calculator is not in BGN mode)
1722.25 PV, -44 PMT, -1100 FV, 30 N, CPT 1/Y.
j can be found to be 1.608245%. The corresponding nominal annual rate compounded semiannually is (X) = i² = 2j =3.216%
Y = -2.8x +69.4
Let y represent units of inventory, and x represent days since the last replenishment. We are given points (x, y) = (3, 61) and (13, 33). The line through these points can be described using the 2-point form of the equation of a line:
... y -y1 = (y2-y1)/(x2 -x1)(x -x1)
Filling in the given point values, we have ...
... y -61 = (33 -61)/(13 -3)(x -3)
Simplifying and adding 61, we get ...
... y = -2.8x +69.4
Answer:
^
Step-by-step explanation: