What is the volume of a sphere with a radius of 60.5 ft, rounded to the nearest tenth of a cubic foot?

Please help and give explanation

Firlakuza [10]

Answer:

100 mins

Step-by-step explanation:

total no of gallons pool can hold=4500

gallons pool already holds=1500

rate of adding water= 30 gallons per min

time he can continue filing= 4500-1500/30

=3000/30

=100 minutes (m value)

correct me if I'm wrong appreciate me if I'm good

8 0

3 years ago

PLZZZZZZ IL do anything give brainilest 5 star i'll like My grade depends on this PLEASE I NEED THIS TO BE CORRECT AND SHOW YOUR

sesenic [268]

Answer:

$195.00

Step-by-step explanation:

perimeter is 54 feet

area is 152 $ft^{2}$

54' * $1.50 = $81.00

152/8 = 19 bags of mulch needed

19*$6.00= $114.00

$195.00 you get away from the store for under 200 :P

P.S. since you said you'll do anything, send me $1,000,000.00 dollars :D

8 0

3 years ago

F(x) = x2 – 2x - 8

maw [93]

Answer:

The y-intercept is the point (0,-8)

see the attached figure

Step-by-step explanation:

we have

$f(x)=x^{2}-2x-8$

we know that

The y-intercept is the value of the function f(x) when the value of x is equal to zero

so

For x=0

$f(x)=0^{2}-2(0)-8\\f(x)=-8$

therefore

The y-intercept is the point (0,-8)

see the attached figure to better understand the problem

5 0

3 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

a)

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

b)

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

10 months ago

Chris bought six pounds of apples for 10.80. How much would 15 pounds of apples cost at the same price per pound?

love history [14]

Answer: $27

Step-by-step explanation: First we would like to know how much it costs per pound of apples. To find that out simply divide 10.80 by 6 to find the price for one pound. 10.80/6 = $1.80 per pound of apples.

Now, we want to find out how much 15 pounds of apples cost. Simply multiply 1.80 x 15 to find the price of 15 pounds of apples. 1.80 x 15 = $27 for 15 pounds of apples.

5 0

2 years ago