Need help asap, it's asking me to find m angle J and that K = 25.

What is the solution set of 7x 2 + 3x = 0? {0, 3/7} {0, -3/7} {0, -4/7}

34kurt

X(7x+3)=0
x=0
or
7x=-3
x=-3/7

so,
(0,0) or (-3/7,0)

5 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

My brothers and sisters i need help asap please

Otrada [13]

Answer:

Step-by-step explanation:

I think it is D but I am not sure

4 0

2 years ago

I need a answer to 77.5% of 13.270

den301095 [7]

Answer:

10.28425

Step-by-step explanation:

4 0

3 years ago

Two liquids Kaylin mixed two liquids for science experiment one container had 7/8 Cup and the other health 9/10 cup what is the

seraphim [82]

Answer:

Step-by-step explanation:

<em>Step 1: Determine quantity per liquid</em>

liquid 1=7/8 cup

liquid 2=9/10 cup

<em>Step 2: Derive expression to calculate total amount of mixture</em>

The expression below can be derived;

T=a+b

where;

T=total amount of mixture

a=total amount of liquid 1

b=total amount of liquid 2

In our case;

a=7/8 cup

b=9/10 cup

replacing;

T=(7/8)+(9/10)=1 31/40 cups

The total amount of mixture=1 31/40 cups

3 0

2 years ago