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grigory [225]
3 years ago
7

State the domain and range of the following relation.

Mathematics
2 answers:
Anna71 [15]3 years ago
6 0

Answer:

D = {–3, –1, 1, 2}; R = {–3, 1, 2, 4}

Step-by-step explanation:

  • We need to understand what is the domain of a function?

<em>The domain is the set of all possible x-values which will make the function "work"</em>

  • We need to understand what is the range of a function?

the range of the function is the set of all values that f(x) = y takes.

In your question,

  • all possible x-values : {–3, –1, 1, 2}
  • all possible y-values : {–3, 1, 2, 4}  

So, the domain and range of the following relation is C

D = {–3, –1, 1, 2}; R = {–3, 1, 2, 4}

<em />

olga nikolaevna [1]3 years ago
5 0

Answer:

Step-by-step explanation:

domain (ur x values) = -3,-1,1,2

range (ur y values) = -3,1,2,4

do not have to write them more then once

answer is C

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3 years ago
1. The sum of two numbers is 64. One of the numbers is 16 more than 3 times the other. Find the
Mamont248 [21]

Answer:

The two numbers are 52 and 12.

Step-by-step explanation:

x+y=64

x=16+3y

Now, substitute the second equation into the first one.

16+3y+y=64

16+4y=64

4y=48

y=12

Substitute 12 into one of the equations in order to find x.

x=16+3(12)

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5 0
3 years ago
N the figure, m || n and x || y. If the m /_15 = 75, find m /_1 .
uranmaximum [27]

Answer:

105°

Step-by-step explanation:

m(15) = 75°

Also it's given that m||n . So taking y as transversal ,

m(15) = m(13) = 75°

Also it's given that x||y . So taking m as transversal ,

m(13) = m(5) = 75°

Now m(5) & m(1) are linear pair. So ,

m(5) + m(1) = 180°

=> 75° + m(1) = 180°

=> m(1) = 180° - 75°

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7 0
3 years ago
Given the equation kx – 17 = 51 + x, where k=1, solve for X.
IgorC [24]

Answer:

  • No solution for x, when k = 1
  • x = 68/(k - 1), when k≠ 1

Step-by-step explanation:

<u>Given the equation</u>

  • kx – 17 = 51 + x, where k = 1,

<u>Solve for x:</u>

  • 1*x - 17 = 51 + x
  • x - 17 = x + 51
  • x - x = 51 + 17
  • 0 = 68,

Incorrect equation, no solution for x when k=1

<u>Solving for x when  k ≠ 1</u>

  • kx - 17 = 51 + x
  • kx - x = 51 + 17
  • x(k - 1) = 68
  • x = 68/(k - 1)
4 0
3 years ago
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