We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
10m.
Step-by-step explanation:
Add up all the areas of the running path and then you can reach to the answer. I got 10m and most probably it should be that only.
Answer:
an equation involving the unknown function y, its derivatives y' and y'', and the variable x.
Step-by-step explanation:
Answer:
3. D
4. A
5. C
6. A
hopefullt this helps!
if its incorect im sorry i tried
