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yulyashka [42]
3 years ago
11

Identify the y-intercept for the line 4x – 2y = 4

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer: (0,-2)

Step-by-step explanation: uhdehdwhehehhH

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In a sample of 8 high school students, they spent an average of 28.8 hours each week doing sports with a sample standard deviati
Alja [10]

Answer:

26.12\:

Step-by-step explanation:

Since the population standard deviation \sigma is unknown, and the sample standard deviation s, must replace it, the t distribution  must be used for the confidence interval.

The sample size is n=8.

The degree of freedom is df=n-1, \implies df=8-1=7.

With 95% confidence level, the \alpha-level(significance level) is 5%.

Hence with 7 degrees of freedom, t_{\frac{\alpha}{2} }=2.365. (Read from the t-distribution table see attachment)

The 95% confidence interval can be found by using the formula:

\bar X-t_{\frac{\alpha}{2}}(\frac{s}{\sqrt{n} } )\:.

The sample mean is \bar X=28.8 hours.

The sample sample standard deviation is s=3.2 hours.

We now substitute all these values into the formula to obtain:

28.8-2.365(\frac{3.2}{\sqrt{8} } )\:.

26.12\:

We are 95% confident that the population mean is between 26.12 and 31.48  hours.

4 0
3 years ago
(8 points) will mark brainliest!! pls help:)
sasho [114]
The answer is -21/8 or -2 5/8
6 0
3 years ago
Find dy/dx by implicit differentiation for ycos(x)=xcos(y)
alekssr [168]

Answer:

dy/dx = (cos y + y sin x) / (cos x + x sin y)

Step-by-step explanation:

y cos x = x cos y

y (-sin x) + dy/dx cos x = x (-sin y dy/dx) + cos y

-y sin x + dy/dx cos x = -x sin y dy/dx + cos y

dy/dx (cos x + x sin y) = cos y + y sin x

dy/dx = (cos y + y sin x) / (cos x + x sin y)

5 0
3 years ago
Adding Expressions
Brut [27]

Answer:

the last one

Step-by-step explanation:

I checked

5 0
4 years ago
Read 2 more answers
Subtract rational expression. <br> Show work please.
yan [13]

Given:

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor x^2-1. It can be written as x^2-1^2.

x^2-1^2=(x-1)(x+1) using algebraic identity.

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}

LCM of x-1,(x+1)(x-1)=(x+1)(x-1)

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

                        $=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}

Now, denominators are same, you can subtract the fractions.

                        $=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}

Expand (x+4)(x+1)-5.

                        $=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}

                        $=\frac{x^{2}+5 x-1}{(x-1)(x+1)}

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}

6 0
3 years ago
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