Let x represent the total number of pupils: (1/3)x = 12
Multiply both sides by 3: x = 36
Total number of pupils is 36
1 pupil out of 36 pupils = 1/36
Answer: 1/36
Answer:
41.4
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj / hyp
cos x = 9/12
Taking the inverse cos of each side
cos ^-1 ( cos x) = cos ^-1 (9/12)
x = 41.41
To the nearest tenth
x = 41.4
Answer:
See below
Step-by-step explanation:
Expand it a bit to see:
= ![\sqrt[5]{ 2^5 * 7 * x^5 * x^5 * x * y^5 * y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%202%5E5%20%2A%207%20%2A%20x%5E5%20%2A%20x%5E5%20%2A%20x%20%2A%20y%5E5%20%2A%20y%5E3%7D)
=![2x^2y \sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E2y%20%5Csqrt%5B5%5D%7B7xy%5E3%7D)
We are starting with y = 3x -5 which is the slope intercept form (y = mx +b) of a linear equation where the slope is m and the y intercept is b. In this equation the slope m = 3 A perpendicular line would have a slope that is the negative reciprocal so the slope of the perpendicular line would be m = -1/3 So we have a slope m = -1/3 and a point (3,2) so use the point slope formula (Y-Y1) = m(X-X1)In this case (X1,Y1) = (3,2) (Y - 2) = (-1/3)(X-3) Y-2 = (-1/3)X + 1 Y = (-1/3)X + 3 would be the equation of the perpendicular line through (3,2)
Answer:
D. There is no evidence to show an increase in the proportion of students attending college because the p-value is less than the alpha level, therefore we will reject the null hypothesis.
Step-by-step explanation:
Assuming a significance level of α=0.05, since 0.000548<0.05, we reject the null hypothesis and conclude that there is no evidence to show an increase in the proportion of students attending college. So option D is correct.
