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Mila [183]
4 years ago
15

Joil wanted to cut the angle into two smaller angles draw and label ray BD to cut angle ABC into two smaller angles with angle D

BC measuring 55 what is the measure of angle ABD

Mathematics
1 answer:
Ann [662]4 years ago
4 0

Answer:

Step-by-step explanation:

I think your question is missing the key information about the degree of the big angle. So please have a look at the attach photo below, it may help you.

the measure of angle ABD = ∠ABC - ∠DBC

= 109 - 55

= 54 degree

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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.
const2013 [10]

Answer:

a.

T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

b.

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

Step-by-step explanation:

Remember that for any curve      r(t)  

The tangent vector is given by

T(t) = \frac{r'(t) }{| r'(t)| }

And the normal vector is given by

N(t) = \frac{T'(t)}{|T'(t)|}

a.

For this case, using the chain rule

r'(t) = (  -10*2tsin(t^2) ,   102t cos(t^2)   )\\

And also remember that

|r'(t)| = \sqrt{(-10*2tsin(t^2))^2  +  ( 10*2t cos(t^2) )^2} \\\\       = \sqrt{400 t^2*(  sin(t^2)^2  +  cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t

Therefore

T(t) = r'(t) / |r'(t) | =  (  -10*2tsin(t^2) ,   10*2t cos(t^2)   )/ 20t\\\\ = (  -10*2tsin(t^2)/ 20t ,   10*2t cos(t^2) / 20t  )\\= ( -sin(t^2), cos(t^2) )

Similarly, using the quotient rule and the chain rule

T'(t) = ( -2t cos(t^2) , -2t sin(t^2))

And also

|T'(t)| = \sqrt{  ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t

Therefore

N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

Notice that

1.   |N(t)| = |T(t) | = \sqrt{ cos(t^2)^2  + sin(t^2)^2 } = \sqrt{1} =  1

2.   N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0

b.

Simlarly

r'(t) = (2t,-6,0) \\

and

|r'(t)| = \sqrt{(2t)^2   + 6^2} = \sqrt{4t^2   + 36}

Therefore

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

Then

T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)

and also

|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 +   ( (3 t)/(9 + t^2)^{3/2})^2  +  0^2 }\\= 3/(t^2 + 9 )

And since

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

6 0
3 years ago
The number of wins for a high school football team is measured for the season. When the team plays at home, it is generally beli
arlik [135]

Answer:

D

Step-by-step explanation:

Given a correlation coefficient of -.11 the correlation would be extremely weak therefore it would have almost no correlation or causation

Why? Well when the value of the correlation is between -.1 and .1 then the relationship is said to have no correlation

-.11 is very close to -.1 thus meaning it would have pretty much no correlation

3 0
3 years ago
Read 2 more answers
What is the value of y?
RUDIKE [14]

Answer:

C. 55

Step-by-step explanation:

Since all angles in a triangle add up to 180°, we have:

40 + y + y + 30 = 180

2y + 70 = 180

2y = 110

y = 55

7 0
3 years ago
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The pool at the park is 18 feet wide how many yardsticks would it take to measure the width of the pool
sattari [20]
6 because 18 divided by 3 equals 6

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3 years ago
If z varies directly with the product of x and y(z=k x y) , then z is said to vary jointly with x and y .
Dafna1 [17]

The value of z varies jointly with w and y.

What is the constant of proportion?

A constant of proportion is illustrated as the ratio which relates two given quantities with each other in the relationship of proportion. Constant of proportion is also called constant variation, rate of change, and constant ratio.

Solving for the value of constant of variation

let k be the constant of proportion

When a quantity varies directly with others, then we have a relation, y = kx

Given relation is z = kxy        —-- 1

Also x varies directly with w i.e. x = k'w, where k' is constant of variation for x and w

Using in equation 1, we have,

z = k(k'w)y

z = kk'wy

z = Kwy, where K is constant of variation i.e. K = kk'

It shows that z varies directly with w and y.

Hence, z varies jointly with w and y.

To learn more about the constant of proportion, visit the link:

brainly.com/question/24868934

#SPJ4

5 0
1 year ago
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