9514 1404 393
Answer:
Step-by-step explanation:
1. The mass of the salt in 100 g of seawater is given as 3.5% of the total mass, so is ...
3.5% × 100 g = 3.5 g . . . . salt in 100 g of seawater
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2. Let m represent the mass of seawater that contains 100 g of salt.
3.5% × m = 100 g
m = (100 g)/0.035 ≈ 2857 g
About 2.857 kg of seawater must evaporate to leave 100 g of salt.*
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* Clearly, only the water evaporates, the mass of the evaporated water is 2.757 kg. The number above is the mass of seawater that is required in order to obtain 100 g of salt. The wording of the problem leaves some ambiguity, it seems.
