Answer:
-12.6
Step-by-step explanation:
OK so I might have done something wrong but just remember when you're adding a negative and and a positive number you're technically just subtracting
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
H(x)=5x+15+4x+20
if x=4, together it would be 5(4)+15+4(4)+20
h(x)=20+15+16+20=71
Divided by 2, they'd each get 35.5
If Frank worked alone, he'd get 5(4)+15= 35
He'd make more working together.
7k/3 = 21
x 3 x3
7k = 63
/7 /7
k = 9
(7(9)/3 = 21 = 63/3 = 21 = 21 = 21)
