Ask question

Ask question

All categories

2 years ago

7

You draw three cards from a deck of cards. Explain the difference in the probability of drawing three kings from the deck if you

pull and replace the card versus you pull and don't replace the card.

1 answer:

8090 [49]2 years ago

8 0

If you replace cards it would be deferent then if you didnt beacuse there would be difrent cards therefore it would change the probability

You might be interested in

Write ‒6x^2 + 13x ‒ 6 as the product of two binomials.

VLD [36.1K]

Should be (x-1.5)(x-2/3)

5 0

2 years ago

Plz help me I need help

drek231 [11]

Answer:

No

Step-by-step explanation:

The two shown sides would have to be and equal solved number.

They are not.

Orange is the correct answer.

7 0

2 years ago

I have no idea how to solve??

kupik [55]

120 = (1/3)b(8) =

B = 120/ (1/3)8

B = 120/ 2 2/3

B = 45

3 0

3 years ago

Oliver sewed a quilt 3 2/3 feet long and 2 1/4 feet wide. what is the area of her quilt?

Hunter-Best [27]

Answer:

8.25 feet

Step-by-step explanation:

3 2/3 times 2 1/4 equals 8.25

4 0

2 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago