Answer:
The correct answer is -
a. the second group that receives test medicine
b. the first group that receives an inert pill
c. double-blind
d. placebo-controlled experiment
Step-by-step explanation:
a. The treatment group is the group that is used to test the experiment or change and receives the desire independent variable which is the second group that receives the test medicine along with an exercise and diet plan.
b. The control group is the group that is placed in ideal condition and receives no change other than placebo, here, the first group receives an inert pill along with the same exercise and diet plan.
c. Here neither the patients nor the fitness and nutrition advisors know which one is the control group and which one is the treatment group so ts a double-blind group.
d. This is best described as a placebo-controlled experiment due to the fact that there is a control group in this experiment that receives a placebo and another group that receives the treatment.
Answer:
The Terry's resultant speed is 27mi/h
Direction of ferry=20°
Step-by-step explanation:
(-25,0) + ( 0, 9)= (-25, -9) is the vector representing the movement of the ferry
Speed of ferry = sqrt[(-25)^2 + (-9)^2]
Speed= sqrt (-625 + (-81))
Speed= sqrt(-706)
Speed=26.57mi/h
Nearest tenth,speed= 27mi/h
Tanz° = (-9/-25)
Tanz°= 0.36
Z°= tan^-1 0.36
Z= 19.80°
Nearest tenth,z=20°
Answer:
On the first one the total is 37500.The second dealer is again,37500.You put a coma after every 3 digit so the coma is 357,000.Sorry if I over explained it.
Answer: Crickets make 172 chirps/min at 80 degrees Fahrenheit
Step-by-step explanation:
Step 1
Using the point slope formulae for Linear functions , we have that
y - y1 = m(x - x1)
where x and y are two points representing the temperature and chirps /min respectively
And
m= slope
Step 2 : Finding the slope , m
where x1=60
y1=92
x2= 75
y2=152
m= (y2-y1)/ (x2-x1)
= (152- 92)/(75-60)
=60/15 =4
Bringing down the point/slope formula and imputing the known values to find our equation to show the relationship cricket make per minute and the temperature
y - y1 = m(x - x1)
y - 92= 4(x - 60)
y - 92 = 4x -240
y = 4x - 240 + 92
y = 4x - 148
Step 3
To find the number of chirps be per minute (y) if the temperature is 80 degrees Fahrenheit( x)
y = 4(80) - 160
y = 320 - 148
y = 172 chirps/min at 80 degrees Fahrenheit
Change the x and y
Then solve for y
X= 8y+1
Subtract 1 from both sides
X-1=8y
Divide by 8
X-1 /8 = y
