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3 years ago

Can anyone help me with this question please no links though. I’ll mark you as a brainliest.

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

3 0

I’m sorry I can’t read that it’s too small..

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Lawrence middle school is painting a circle on their playground with a radius of 7 feet what will be the total area of the circl

mars1129 [50]

Answer:

The answer will be 153.9

Step-by-step explanation:

multiply 3.14 and 7 square and that is your answer

4 0

2 years ago

You are making a walkway around part of a swimming pool. The dimensions of the swimming pool are 18 and 25, while the dimensions

vredina [299]

Answer:

$A = 4x^2 + 86x + 450$

Step-by-step explanation:

Given

$Walkway = x$

$Length = 18$

$Width = 25$

Required:

The area of the swimming pool

Assume the walkway will be on the 4 sides of the swimming pool.

The total length (L) of the swimming pool will be:

$L = 18 + x + x$

$L = 18 + 2x$

The total width (W) will be:

$W = 25 + x + x$

$W = 25 + 2x$

The area (A) is:

$A = L * W$

$A = (18 + 2x) * (25 + 2x)$

Expand bracket

$A = 18 * 25 + 18 * 2x + 25 * 2x + 2x * 2x$

$A = 450 + 36x + 50x + 4x^2$

$A = 450 + 86x + 4x^2$

Reorder

$A = 4x^2 + 86x + 450$

8 0

3 years ago

What is the measure of SQ? 1. 95 2. 190 3. 265 4. 360

Vesnalui [34]

Answer:

The measure of arc SQ is 95° ⇒ (1)

Step-by-step explanation:

The measure of any circle is 360°

The measure of the subtended arc to an inscribed angle is twice the measure of this angle

In the given circle

∵ S lies on the circumference of the circle

∴ ∠QSR is an inscribed angle

∵ ∠QSR is subtended by arc QR

→ By using the 2nd rule above

∴ m arc QR = 2 × m∠QSR

∵ m∠QSR = 95°

∴ m arc QR = 2 × 95

∴ m arc QR = 190°

→ By using the 1st rule above

∵ m of the circle = m arc QR + m arc SQ + m arc SR

∵ m arc SR = 75° and m arc QR = 190°

→ Substitute them in the equation above

∴ 360 = 190 + m arc SQ + 75

→ Add the like term in the right side

∴ 360 = 265 + m arc QS

→ Subtract 265 from both sides

∵ 360 - 265 = 265 - 265 + m arc SQ

∴ 95° = m arc SQ

∴ The measure of arc SQ is 95°

7 0

3 years ago

If you subtract 12-7.28 what is your answer ?

KiRa [710]

Use a calculator and get 4.72

8 0

3 years ago

4. As shown in Figure 5.111 to the right if the

Juli2301 [7.4K]

Answer:

Area of the shaded part is 3.14 square unit.

Step-by-step explanation:

Area of the shaded part = Area of large semicircle - (Area of two small semi circles)

Area of large semicircle with center O = $\frac{1}{2}(\pi r^2)$

= $\frac{1}{2}\pi (2)^{2}$

= 2π

Area of semicircle with center O' = $\frac{1}{2}\pi (1)^2$

= $\frac{\pi }{2}$

Area of semicircle with center O" = $\frac{\pi }{2}$

Now substitute these values in the formula,

Area of shaded part = $2\pi - (\frac{\pi }{2}+\frac{\pi }{2})$

= $\pi$

= 3.14 square unit

Area of the shaded part is 3.14 square unit.

7 0

2 years ago