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goldenfox [79]
3 years ago
6

Does this graph show a function?

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

9514 1404 393

Answer:

  A

Step-by-step explanation:

A vertical line intersects the graph in <em>more than one place</em>. As a consequence, we say the graph "fails the vertical line test." When the test fails, the graph is not a graph of a function.

You might be interested in
The equation 9.95 + 0.30s=c gives the cost c in dollars that a website charges for downloading songs. The variable s stands for
IrinaK [193]

Answer:

$20.45

Step-by-step explanation:

First substitute 35 for s

9.95+0.30(35)=c<-----

If you solve this you would get...

$20.45

3 0
3 years ago
1.
OlgaM077 [116]

Answer:

<h3>           A.   A = 66π cm² ≈ 207.35 cm²</h3><h3>           B.  No, will not. {will be less than double}</h3><h3>           C.  No, will not. {will be more than double}</h3>

Step-by-step explanation:

<h3>A.</h3>

h = 8 cm,  r = 3 cm

A = 2×πr² + 2πr×h = 2πr×(r + h)

A = 2π×3×(3 + 8) =  66π cm² ≈ 207.35 cm²

<h3>B.</h3>

h = 2×8 = 16 cm ,      r = 3 cm ,   2×66π = 132π cm²

A = 2π×3×(3 + 16) =  114π cm² ≠ 132π cm²  

<h3>C.</h3>

h = 8 cm ,        r = 2×3 = 6 cm  ,   2×66π = 132π cm²

A = 2π×6×(6 + 8) =  168π cm² ≠ 132π cm²    

4 0
3 years ago
How many time does 80 fit into 415
Elza [17]

Answer:

5 times

Step-by-step explanation:

have a good day/night :)

6 0
3 years ago
Read 2 more answers
What is the answer?
Vinvika [58]

Answer:

1:200

5.6 cm^2 : y (as actual area)

y = 200 mutifly 5.6 cm^2

y= 1120 cm^2

We know 1m =100cm

so, 1m^2 =100cm x 100 cm = 1000cm^2

y= 1120 m^2/ 100x100

 = 0.112 m^2

Step-by-step explanation:

8 0
3 years ago
Solve for b2 in A = 1/2 h(b1+b2), if A = 16, h = 4, and b1 = 3. 16= 1/2* 4(3+b2) =6+2b2 or, b2= [16-6]/2= 5
Tatiana [17]
Assuming you are referring to the area of a "trapezoid"; in which one calculates the Area, "A", as follows:
________________________
<span> A = 1/2* h(b1+b2) ;

in which: A = Area = 16 (given); 
               h = height = 4 (given);
               b1 = length of one of the two bases = 3 (given);
               b2 = length of the other of the two bases = ? (what we want to solve                                                                                            for) ;
______________________________________________________
Using the formula: </span>A = 1/2 h(b1+b2) ;
________________________________
Let us plug in our known values:
___________________________
 →  16 = (1/2) * 4*(3 + b2) ;  → Solve for "b2".
________________________________
 →Note: On the "right-hand side" on this equation: "(1/2)*(4) = 2 ." 
________________________________
 So, we can rewrite the equation as:
________________________________
 → 16 =   2*(3 + b2) ;  → Solve for "b2".
________________________________
We can divide EACH side of the equation by "2"; to cancel the "2" on the "right-hand side" of the equation:
________________________________
 → 16 / 2 =   [2*(3 + b2)] / 2  ;  → to get:
___________________________
8 = (3 + b2) ;
_________________
 → Rewrite as: 8 = 3 + b2;
_______________________
Subtract "3" from EACH side of the equation; to isolate "b2" on one side of the equation; and to solve for "b2" :
______________________________
 → 8 - 3 = 3 + b2 - 3 ;  → to get:
_____________________
b2 = 5;  From the 2 (TWO) answer choices given, this value,
"b2 = 5", corresponds with the following answer choice:
____________________
b2= [16-6]/2= 5 ; as this is the only answer choice that has: "b2 = 5".
<span>_________________________________________

As far getting "</span>b2 = 5"  from: "b2= [16-6]/2= 5"; (as mentioned in the answer choice), we need simply to approach the problem in a slightly different manner.  Let us do so, as follows:
<span>_____________________________________
Start from: </span>A = 1/2 h(b1+b2); and substitute our known (given) values):<span>
________________________
</span>→ 16 = (1/2) *4 (3 + b2) ; → Solve for "b2".
_____________________________
Note that: (½)*4 = 2;  so we can substitute "2" for: "(1/2) *4" ; 
and rewrite the equation as follows:
_________________________
→ 16 = 2 (3 + b2) ;
____________________
Note: The distributive property of multiplication:
_________________________
a*(b+c) = ab + ac ;
_________
As such: 2*(3 + b2) = (2*3 + 2*b2) = (6 + 2b2). 
_________________
So we can substitute: "(6 + 2b2)" in lieu of "[2*(3 + b2)]"; and can rewrite the equation:
______________________
→ <span>16 = 6 + 2(b2) ; Now, we can subtract "6" from EACH side of the equation; to attempt to isolate "b2" on one side of the equation:</span>
<span>________________________________________________
 </span>→ 16 - 6 =  6 + 2(b2) - 6 ;
      → Since "6-6 = 0"; the "6 - 6" on the "right-hand side" of the equation cancel.
→ We now have: 16 - 6 = 2*b2 ; 
___________
Now divide EACH SIDE of the equation by "2"; to isolate "b2" on one side of the equation; and to solve for "b2":
____________________
   → (16 - 6) / 2 = (2*b2) / 2 ; 
     → (16 - 6) / 2 = b2 ;
       → (10) / 2 = b2 = 5.
______________
NOTE: The other answer choice given: 
_____________
"<span>16= 1/2* 4(3+b2)= 6+2b2" is incorrect; since it does not solve for "b2".</span>
3 0
3 years ago
Read 2 more answers
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