How many gallons in a 100 lb propane tank?

Daeja and Juana solved this equation 6 = 1/2s.

xz_007 [3.2K]

Answer:

Daeja is correct.

Step-by-step explanation:

Equation: 6 = 1/2s

Solve:

(2)6 = 1/2s(2) <== multiply both sides by 2

12 = s or s = 12

Therefore, Daeja is correct.

I multiplied both sides by 2 to isolate s, and 2 ⋅ 6 is 12.

Hope this helps!

5 0

2 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

Why 2 is not a solution of x>5

NikAS [45]

Answer:

X has to be bigger than 5 and 2 is lower than 5.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the standard deviation for 0,0,0,1,1,1,2,2,3,5?

Nadya [2.5K]

Standard Deviation, σ: 1.5
Count, N: 10
Sum, Σx: 15
Mean, μ: 1.5
Variance, σ2: 2.25

Steps

σ2 =
Σ(xi - μ)2
N
=
(0 - 1.5)2 + ... + (5 - 1.5)2
10
=
22.5
10
= 2.25
σ = √2.25
= 1.5

4 0

1 year ago

Read 2 more answers

The area of a rectangular computer screen is 4x^2+20x+16. The width of the screen is 2x+8. What is the length of the screen?

Aleksandr-060686 [28]

So the area of a rectangle is Length x Width.
A = (L)(W)
Substitute the information given:
4x^2 + 20x + 16 = (L)(2x+8)
Isolate L by dividing 2x+8:
(4x^2 + 20x +16)/ (2x + 8) = L
If you divide:
L = 2x + 2.

7 0

4 years ago