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bazaltina [42]
3 years ago
5

Khan Academy please show work​

Mathematics
1 answer:
Temka [501]3 years ago
4 0

Answer:

Rewriting the equation in the form (x+c)²=d by completing the square

  • \left(x+5\right)^2=16

The solutions to the quadratic equation are:

  • x=-1,\:x=-9

Step-by-step explanation:

Given the equation

x^2+10x+22=13

subtract 22 from both sides

x^2+10x+22-22=13-22

simplify

x^2+10x=-9

Rewriting the equation in the form (x+c)²=d by completing the square

x^2+10x+5^2=-9+5^2

x^2+10x+5^2=16

\left(x+5\right)^2=16

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{16}

x+5=\sqrt{4^2}

x+5=4

x=-1

also solving

x+5=-\sqrt{16}

x+5=-4

x=-9

Therefore, the solutions to the quadratic equation are:

x=-1,\:x=-9

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Answer:

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Step-by-step explanation:

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5 0
2 years ago
A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const
Ludmilka [50]

Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

3 0
4 years ago
Which of the following are the coordinates of the vertex of y = x2 − 10x + 2?
olga55 [171]

y=x^2 - 10x +2


Use the form ax^2 + bx + c to find the values of a, b,and c.

a = 1 ( no number in front of the x^2)

b = 10

c = 2


Vertex form is a(x+d)^2 + e

Solve for d using d= b/2a

d = 10 / 2

d = 5


Find e using e = c - b^2/4a

e = 2 - 10^2/4

e = 2 - 25

e = -23


Vertex = d,e

Vertex = (5, -23)

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