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Sergio [31]
3 years ago
11

A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const

ruct a 90% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Is it safe to conclude that the population standard deviation is less than 1.40°F​?
_____°F


Is it safe to conclude that the population standard deviation is less than 1.40°F​?


A. This conclusion is not safe because 1.40 °F is in the confidence interval.


B. This conclusion is safe because 1.40 °F is in the confidence interval.


C. This conclusion is not safe because 1.40°F is outside the confidence interval.


D. This conclusion is safe because 1.40 °F is outside the confidence interval.
Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

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For Question 1:

Date             Account Titles and Explanation                   Dr              Cr

31-Jan-2024              Revenue Service                      $17,500  

                                   Summary of Income                                    $17,500

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                                  Expense of Salary                                     $3,600

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                        Expense of Depreciation - equipment                   $300

                               Expense on Supplies                                            $400

                                 Expense on Utilities                                           $1,000

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For Question 2:

A net income of $10,400 is generated. They may compute it by subtracting total expenses from the entire revenue.

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  • Please find the complete question in the attachment file.

Learn more:

brainly.com/question/14695332

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